36x^2-25=5x

Solution for 36x^2-25=5x equation:

36x^2-25=5x

We move all terms to the left:

36x^2-25-(5x)=0

a = 36; b = -5; c = -25;
Δ = b2-4ac
Δ = -52-4·36·(-25)
Δ = 3625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3625}=\sqrt{25*145}=\sqrt{25}*\sqrt{145}=5\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5\sqrt{145}}{2*36}=\frac{5-5\sqrt{145}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5\sqrt{145}}{2*36}=\frac{5+5\sqrt{145}}{72}
$